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this is nice too
The first way shown is:
(a) incorrect
(b) horrendously WRONG CALCULATION! It shows, for instance, (201 + 210)/2 = 411/2 = 205.5 --> and how is THAT equal to 210.5???!! MORON!!
People like you are a waste of space. American, I suppose?
@Aman, Thanks Aman for correction. Although the language used was a bit harsh but we don't mind because we believe in democracy. If you have found some other mistakes please do tell us in your own style we will never mind. Thanks again
210-211/2 =0.5 now subtract it to the lower class and add to the upper simple
mr aman i think u dint see it that way its 210+210/2=210.5..whch is abslutly crct...
The trick is that sometimes the sum of lower and upper class limit may be an even number, and when that sum is divided by two, the resulting answer will a whole number. How can the class boundaries be calculated?
How do u get the class boundaries for decimal numbers? Let say interval is 4.8 - 5.3. I've been having difficulty looking for solutions for it.
Thanks a lot in advance. :-)
Mr. Aman, if there are problems or if there is a need for correction, just tell it nicely to the one who posted it. Don't use unnecesesary words.
how to calculate upper boundary for ungroup data according to analysis of business
Good work by the person who posted it, . , Mughal got it quite nicely, . ,
What is the class mid-value of a class of 0 - 10 using the two methods above (using limits and boundaries)?