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<p align="justify">An empirical relationship exists between mean, median and mode. For a moderately skewed distribution it is:</p>
<p align="justify">&#160;</p>
<p align="justify"><a href="http://mba-lectures.com/wp-content/uploads/2010/06/image14.png"><img title="image" style="border-top-width: 0px; display: inline; border-left-width: 0px; border-bottom-width: 0px; border-right-width: 0px" height="38" alt="image" src="http://mba-lectures.com/wp-content/uploads/2010/06/image_thumb14.png" width="240" border="0" /></a> </p>
<p align="justify">&#160;</p>
<ul>
<li>
<div>If a frequency distribution has a symmetrical frequency curve, the mean, median and mode are equal. </div>
</li>
</ul>
<p> &#160;</p>
<p> <a href="http://mba-lectures.com/wp-content/uploads/2010/06/image15.png"><img title="image" style="border-top-width: 0px; display: inline; border-left-width: 0px; border-bottom-width: 0px; border-right-width: 0px" height="132" alt="image" src="http://mba-lectures.com/wp-content/uploads/2010/06/image_thumb15.png" width="400" border="0" /></a> </p>
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<p> &#160;</p>
<ul>
<li>If a frequency distribution is positively skewed, then mean is greater than median and median is greater than mode. </li>
</ul>
<p> &#160;</p>
<p> <a href="http://mba-lectures.com/wp-content/uploads/2010/06/image16.png"><img title="image" style="border-top-width: 0px; display: inline; border-left-width: 0px; border-bottom-width: 0px; border-right-width: 0px" height="117" alt="image" src="http://mba-lectures.com/wp-content/uploads/2010/06/image_thumb16.png" width="400" border="0" /></a> </p>
<p> &#160;</p>
<ul>
<li>If a frequency distribution is negatively skewed, then mean is less than median and median is less than mode. </li>
</ul>
</p>
<p>&#160;</p>
<p> <a href="http://mba-lectures.com/wp-content/uploads/2010/06/image17.png"><img title="image" style="border-top-width: 0px; display: inline; border-left-width: 0px; border-bottom-width: 0px; border-right-width: 0px" height="120" alt="image" src="http://mba-lectures.com/wp-content/uploads/2010/06/image_thumb17.png" width="400" border="0" /></a> </p>
<p> &#160;</p>
<p> Since median always lies between mean and mode in a moderately skewed distribution, therefore it is considered as most realistic measure of central tendency.</p>
<p><strong>Problem:</strong> For a moderately skewed distribution mode = 50.04, mean = 45, Find median. </p>
<p> &#160;
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View Comments
It doesn't always work
Can i write it as 3median = mode 1+ 2mean
despite the facts that you have interesting topics i cannot copy to do revision when i am chanced and my e-mail is not accepted thanks